S If 12.6 moles of Cu and 46.8 moles of HNO3 are allowed to react, how many moles of excess reactant

s

If 12.6 moles of Cu and 46.8 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction
goes to completion?
3 Cu + 8 HNO3 — 3Cu(NO3)2 + 2NO + 4H20